pandas.DataFrame.mean#
- DataFrame.mean(*, axis=0, skipna=True, numeric_only=False, **kwargs)[source]#
Return the mean of the values over the requested axis.
- Parameters:
- axis{index (0), columns (1)}
Axis for the function to be applied on. For Series this parameter is unused and defaults to 0.
For DataFrames, specifying
axis=None
will apply the aggregation across both axes.Added in version 2.0.0.
- skipnabool, default True
Exclude NA/null values when computing the result.
- numeric_onlybool, default False
Include only float, int, boolean columns.
- **kwargs
Additional keyword arguments to be passed to the function.
- Returns:
- Series or scalar
Value containing the calculation referenced in the description.
See also
Series.sum
Return the sum.
Series.min
Return the minimum.
Series.max
Return the maximum.
Series.idxmin
Return the index of the minimum.
Series.idxmax
Return the index of the maximum.
DataFrame.sum
Return the sum over the requested axis.
DataFrame.min
Return the minimum over the requested axis.
DataFrame.max
Return the maximum over the requested axis.
DataFrame.idxmin
Return the index of the minimum over the requested axis.
DataFrame.idxmax
Return the index of the maximum over the requested axis.
Examples
>>> s = pd.Series([1, 2, 3]) >>> s.mean() 2.0
With a DataFrame
>>> df = pd.DataFrame({'a': [1, 2], 'b': [2, 3]}, index=['tiger', 'zebra']) >>> df a b tiger 1 2 zebra 2 3 >>> df.mean() a 1.5 b 2.5 dtype: float64
Using axis=1
>>> df.mean(axis=1) tiger 1.5 zebra 2.5 dtype: float64
In this case, numeric_only should be set to True to avoid getting an error.
>>> df = pd.DataFrame({'a': [1, 2], 'b': ['T', 'Z']}, ... index=['tiger', 'zebra']) >>> df.mean(numeric_only=True) a 1.5 dtype: float64