pandas.Index.union#
- final Index.union(other, sort=None)[source]#
Form the union of two Index objects.
If the Index objects are incompatible, both Index objects will be cast to dtype(‘object’) first.
- Parameters:
- otherIndex or array-like
Index or an array-like object containing elements to form the union with the original Index.
- sortbool or None, default None
Whether to sort the resulting Index.
None : Sort the result, except when
self and other are equal.
self or other has length 0.
Some values in self or other cannot be compared. A RuntimeWarning is issued in this case.
False : do not sort the result.
True : Sort the result (which may raise TypeError).
- Returns:
- Index
Returns a new Index object with all unique elements from both the original Index and the other Index.
See also
Index.unique
Return unique values in the index.
Index.intersection
Form the intersection of two Index objects.
Index.difference
Return a new Index with elements of index not in other.
Examples
Union matching dtypes
>>> idx1 = pd.Index([1, 2, 3, 4]) >>> idx2 = pd.Index([3, 4, 5, 6]) >>> idx1.union(idx2) Index([1, 2, 3, 4, 5, 6], dtype='int64')
Union mismatched dtypes
>>> idx1 = pd.Index(["a", "b", "c", "d"]) >>> idx2 = pd.Index([1, 2, 3, 4]) >>> idx1.union(idx2) Index(['a', 'b', 'c', 'd', 1, 2, 3, 4], dtype='object')
MultiIndex case
>>> idx1 = pd.MultiIndex.from_arrays( ... [[1, 1, 2, 2], ["Red", "Blue", "Red", "Blue"]] ... ) >>> idx1 MultiIndex([(1, 'Red'), (1, 'Blue'), (2, 'Red'), (2, 'Blue')], ) >>> idx2 = pd.MultiIndex.from_arrays( ... [[3, 3, 2, 2], ["Red", "Green", "Red", "Green"]] ... ) >>> idx2 MultiIndex([(3, 'Red'), (3, 'Green'), (2, 'Red'), (2, 'Green')], ) >>> idx1.union(idx2) MultiIndex([(1, 'Blue'), (1, 'Red'), (2, 'Blue'), (2, 'Green'), (2, 'Red'), (3, 'Green'), (3, 'Red')], ) >>> idx1.union(idx2, sort=False) MultiIndex([(1, 'Red'), (1, 'Blue'), (2, 'Red'), (2, 'Blue'), (3, 'Red'), (3, 'Green'), (2, 'Green')], )